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Sagot :
Answer:
She will need 41.22 meters.
Step-by-step explanation:
She knows that one leg of the triangle is 11 meters long and that the angle formed by that leg and the hypotenuse is 50 degrees .
The leg is adjacent to the hypothenuse. We know that the cosine of an angle [tex]\theta[/tex] is given by:
[tex]\cos{\theta} = \frac{l}{h}[/tex]
In which l is the length of the adjacent side and h is the hypothenuse.
Considering that we have [tex]\theta = 50, l = 11[/tex], we can find the hypothenuse.
Looking at a calculator, the cosine of 50 degrees is 0.6428.
So
[tex]0.6428 = \frac{11}{h}[/tex]
[tex]0.6428h = 11[/tex]
[tex]h = \frac{11}{0.6428}[/tex]
[tex]h = 17.11[/tex]
The other leg:
In a right triangle, with legs [tex]l_1[/tex] and [tex]l_2[/tex], and hypothenuse h, the pythagorean theorem states that:
[tex]l_1^2 + l_2^2 = h^2[/tex]
We already have one of the legs and the hypothenuse, so:
[tex]11^2 + l^2 = 17.11^2[/tex]
[tex]l^2 = 17.11^2 - 11^2[/tex]
[tex]l = \sqrt{17.11^2 - 11^2}[/tex]
[tex]l = 13.11[/tex]
How many meters will she need?
This is the perimeter of the garden, which is the sum of its dimensions, of 11 meters, 13.11 meters and 17.11 meters. So
[tex]P = 11 + 13.11 + 17.11 = 41.22[/tex]
She will need 41.22 meters.
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