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Use the completing the square to solve x^2+6x=12.

Sagot :

763396

Answer:

x= -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex]+6x=12

We add 9 [[tex](6/2)^{2}[/tex]] to both sides to complete the square as [tex]x^{2}[/tex]+6x+9 = [tex](x+3)^{2}[/tex].

[tex](x+3)^{2}[/tex]=21

Now we take the square root of both sides:

x+3=±[tex]\sqrt{21}[/tex]

x= -3 ± [tex]\sqrt{21}[/tex]

Answer:

x = -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^2+6x=12[/tex]

[tex](\frac{b}{2} )^{2}[/tex] = 9

[tex]x^2+6x + 9 =12 + 9[/tex]

[tex](x+3)^{2} =21[/tex]

x + 3 = [tex]\sqrt{21}[/tex]

x = -3 ± [tex]\sqrt{21}[/tex]

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