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Sagot :
Answer:
x= -3 ± [tex]\sqrt{21}[/tex]
Step-by-step explanation:
[tex]x^{2}[/tex]+6x=12
We add 9 [[tex](6/2)^{2}[/tex]] to both sides to complete the square as [tex]x^{2}[/tex]+6x+9 = [tex](x+3)^{2}[/tex].
[tex](x+3)^{2}[/tex]=21
Now we take the square root of both sides:
x+3=±[tex]\sqrt{21}[/tex]
x= -3 ± [tex]\sqrt{21}[/tex]
Answer:
x = -3 ± [tex]\sqrt{21}[/tex]
Step-by-step explanation:
[tex]x^2+6x=12[/tex]
[tex](\frac{b}{2} )^{2}[/tex] = 9
[tex]x^2+6x + 9 =12 + 9[/tex]
[tex](x+3)^{2} =21[/tex]
x + 3 = [tex]\sqrt{21}[/tex]
x = -3 ± [tex]\sqrt{21}[/tex]
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