Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
b; ∀x P(x) ∨ ¬P(x)
Step-by-step explanation:
Suppose that we have a proposition p
Such that p can be true or false.
We can define the negation of p as:
¬p
Such that, if p is false, then ¬p is true
if p is true, then ¬p is false.
Also remember that a proposition like:
p ∨ q
is true when, at least one, p or q, is true.
Then if we write:
p ∨ ¬p
Always one of these will be true (and the other false)
Then the statement is true.
And if the statement depends on some variable, then we will have that:
p(x) ∨ ¬p(x)
is true for all the allowed values of x.
from this, we can conclude that the statement that is always true is:
b; ∀x P(x) ∨ ¬P(x)
Where here we have:
For all the values of x, P(x) ∨ ¬P(x)
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.