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In AABC, point D is the centroid, and AD= 12. Find AG

In AABC Point D Is The Centroid And AD 12 Find AG class=

Sagot :

CoastsideDad

Answer:

AG = 18

Step-by-step explanation:

The relationship of the segments created is one is 1/3 (shorter) and the other (longer) is 2/3 of the total length.

Lets make x represent AG.

So, 2/3 of x is 12

or

[tex]\frac{2}{3}[/tex]x = 12

Multiply both sides by the reciprocal of [tex]\frac{2}{3}[/tex] , which is [tex]\frac{3}{2}[/tex].

( [tex]\frac{3}{2}[/tex]) [tex]\frac{2}{3}[/tex]x = 12 ([tex]\frac{3}{2}[/tex])  (x is left alone, the fractions = 1 when multiplied)

x = 12 ([tex]\frac{3}{2}[/tex])         ( 12 times 3 = 36, divided by 2 = 18)    

x = 18

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