Hello,
[tex]u_0=4000\\u_1=4000*1.05 (for\ year\ 2011)\\\\u_n=4000*1.05^n\\So:\\year\ 2017: u_7=4000*1.05^7=5628,401690625\ \approx{5628}[/tex]
Using an exponential function, the number of students y in the graduating class 7 years after 2010 i.e. in 2017 will be 5628.4
y = abˣ, where a is the initial population, b is the rate, and x is the time, is the standard exponential function.
Here initial student population = 4000.
Rate = 5% = (100 + 5)/100 = 1.05
Time = 7 years.
Now, in 2017, the population will be y = 4000 * (1.05)⁷ = 5628.401691 ≅ 5628.4.
Therefore, using an exponential function, the number of students y in the graduating class 7 years after 2010 i.e. in 2017 will be 5628.4
Learn more about exponential function here -
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