andrewvasquez093
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1) Find the measure of 0. (imagine that is an x) 2) Then, find the measure of AB. (the length from A to B) ​

1 Find The Measure Of 0 Imagine That Is An X 2 Then Find The Measure Of AB The Length From A To B class=

Sagot :

Answer:

θ ≈ 50°, AB ≈ 15.6

Step-by-step explanation:

Using the tangent ratio in the right triangle

tanθ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{11.9}{10}[/tex] = 1.19 , then

θ = [tex]tan^{-1}[/tex] (1.19 ) ≈ 50° ( to the nearest degree

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Using the cosine ratio in the right triangle

cos50° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{10}{AB}[/tex] ( multiply both sides by AB )

AB × cos50° = 10 ( divide both sides by cos50° )

AB = [tex]\frac{10}{cos50}[/tex] ≈ 15.6 ( to 1 dec. place )

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