Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

What is the equation of the line that passes through the given point and is perpendicular to the given line?

Point: (1,1)
Line: y=15x+45


Sagot :

Answer:

y= -1/15x + 16/15

Step-by-step explanation:

When two lines are perpendicular to each other that means their slopes are the negative reciprocals of each other.

So that means if a line has has a slope of 6, a line perpendicular to that line will have a slope of -1/6.

(a reciprocal is when the fraction is flipped over)

In this case, the negative reciprocal of 15 would be -1/15. So the slope of the line that is perpendicular would be -1/15.

The equation we would have so far for that line would be: y=-1/15x+b

Now we have to find the 'b' or the y intercept, which we can get by plugging in the point that was given (1,1), which is on that line.

Which gives us 1=-1/15(1)+b.

1=-1/15+b

1+1/15=b

Then you solve for b and get b= 16/15.

The equation of the line that is perpendicular to the given line is y= -1/15x + 16/15.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.