80100
Answered

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what are the x- intercepts of the function f(x)= -2x-3+20?

Sagot :

angrykai23

Answer:

x = .464

Step-by-step explanation:

Assumptions: Equation is [tex]-2x^3+20[/tex]. Thus having an asymptote at the value x=0.

  • To solve for the x-intercepts, we plug in 0 for f(x).
  • We can subtract 20 from both sides, leaving us with [tex]-20 = -2x^-3.[/tex]
  • We can divide both sides by -2. [tex]10=1/x^3[/tex].
  • Now we multiply both sides by x^3, to get rid of the denominator on the right-hand side. [tex]10x^3=1[/tex].
  • We now divide both sides by 10 and take the cube root. Leaving us with x = [tex]\sqrt[3]{1/10}[/tex] or .464. (One x-intercept.)
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