Answered

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Can you help me with this question? It’s in the photo

Can You Help Me With This Question Its In The Photo class=

Sagot :

Numenius

Answer:

Option (d), (e) and (f) are correct.

Step-by-step explanation:

In triangle MNP, angle P = 90 degree

Cos M = 7 / 12

Now according to the right angle triangle

[tex]NP^2 = NM^2 - PM^2\\\\NP^2 = 12^2 - 7^2\\\\NP = \sqrt95[/tex]

Now

[tex]Sin M = \frac{sqrt95}{12}\\\\Cos N = \frac{95}{12}[/tex]

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