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Sagot :
Answer:
[tex]\frac{1}{12}[/tex] probability of getting a head on the coin and the number 2 on the die
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Independent events:
If two events, A and B are independent, the probability of both events happening is the multiplication of the probabilities of each event happening, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
Probability of getting a head on the coin:
Head or tails, fair coin, so:
[tex]P(A) = \frac{1}{2}[/tex]
Probability of getting the number 2 on the die:
6 numbers, one of which is 2, so:
[tex]P(B) = \frac{1}{6}[/tex]
What is the probability of getting a head on the coin and the number 2 on the die?
[tex]P(A \cap B) = P(A)P(B) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}[/tex]
[tex]\frac{1}{12}[/tex] probability of getting a head on the coin and the number 2 on the die
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