Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
Percent yield of ether = 83.18%
Explanation:
Equation of the synthesis reaction of ether from ethanol is given as follows :
2 C₂H₅OH -----> C₂H₅OC₂H₅ + H₂0
Density = mass / volume
Therefore mass = density × volume
Density of ether = 0.7134 g/mL; volume of ether produced = 1.11 L = 1110 mL; Molar mass of ether = 74 g/mol
Mass of ether produced = 0.7134 g/mL × 1110 mL = 791.874 g
Density of ethanol = 0.789 g/mL; volume of ethanol = 1.50 L = 1500 mL; molar mass of ethanol = 46 g/mol
Mass of ethanol reacted = 0.789 g/mL × 1500 mL = 1183.5 g
From the equation of reaction, 2 mole of ethanol produces 1 mole of ether
Mass of 2 moles of ethanol = 2 × 46 = 92 g
Therefore, 92 g of ethanol produces 74 g of ether
1183.5 g of ethanol will produce 1183.5 × 74/92 grams of ether = 951.945 g of ether
Percent yield of ether = actual yield/theoretical yield × 100%
Actual yield of ether = 791.874 g; theoretical yield of ether = 951.945 g
Percent yield of ether = (791.874 g × 951.945 g) × 100 %
Percent yield of ether = 83.18%
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.