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Sagot :
Given:
The equation of a linear function is:
[tex]y=-\dfrac{2}{3}x-1[/tex]
To find:
The y-intercept and slope of the given equation, then draw the graph of the equation.
Solution:
Slope intercept form of a line is:
[tex]y=mx+b[/tex] ...(i)
Where, m is the slope and b is the y-intercept
We have,
[tex]y=-\dfrac{2}{3}x-1[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]m=-\dfrac{2}{3}[/tex]
[tex]b=-1[/tex]
Therefore, the y-intercept is -1 and the slope of the line is [tex]-\dfrac{2}{3}[/tex].
It means the graph intersect the y-axis at point (0,-1) and having slope [tex]-\dfrac{2}{3}[/tex]. So, the graph of the equation is shown below.
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