Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

In a softball game a batter hits at the velocity of 28 and an angle shown 45 below . What is the maximum range of the ball

Sagot :

fichoh

Answer:

80 m

Explanation:

Given :

Initial Velocity, U = 28 m/s

θ = 45°

The maximum range occurs at angle, θ = 45°

The maximum range, R is given by ;

R = U²sin2θ / g

g = acceleration due to gravity = 9.8 m/s²

Plugging in the values :

R = [28² * sin2(45)] / 9.8

R = [28² * sin90] / 9.8

R = 784 / 9.8

R = 80 m

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.