Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Glycerin, , is a nonvolatile liquid. What is the vapor pressure of a solution made by adding glycerin to at

Sagot :

Complete question is;

Glycerin, C3H8O3, is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 164 g glycerin to 338 mL H2O ​at 39.8°C?

The vapor pressure of pure water at 39.8°C is 54.74 torr and its density is 0.0992 g/cm³

Answer:

28 torr

Explanation:

Let's first find the number of moles of water in 338 mL.

Molar mass of water = 18 g/mole

Formula for number of moles = mass/molar mass.

Mass = density × volume = 0.0992 × 338 = 33.5296 g

Thus;

Number of moles = 33.5296/18 = 1.863 moles.

Let's use the same procedure to find the Number of moles of glycerine.

Molar mass of glycerine from online values = 92.1 g/mol

Thus;

n_glycerine = (mass)/92.1

We have mass and density as 164 g and 0.0992 g/cm³ respectively.

n_glycerine = 164/92.1

n_glycerine = 1.78

Total moles of solution = 1.863 + 1.78 = 3.643 moles

We are told that The vapor pressure of pure water at 39.8°C is 54.74 torr

Thus, since water dominates, then vapour pressure of solution = (1.863/3.643) × 54.74 ≈ 28 torr

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.