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Find a vector equation and parametric equations for the line The line through the point (2, 2.4, 3.5) and parallel to the vector 3i 1 2j 2 k

Sagot :

MrRoyal

Answer:

The vector equation

[tex]r = (2 + 3t)i+ (2.4 + 2t)j+ (3.5 - t)k[/tex]

The parametric equation

[tex]x = 2 + 3t\\y = 2.4 + 2t\\z = 3.5-t[/tex]

Step-by-step explanation:

Given

[tex]Point = (2,2.4,3.5)[/tex]

[tex]Vector = 3i + 2j - k[/tex]

Required

The vector equation

First, we calculate the position vector of the point.

This is represented as:

[tex]r_0 = 2i + 2.4j + 3.5k[/tex]

The vector equation is then calculated as:

[tex]r = r_o + t * Vector[/tex]

[tex]r = 2i + 2.4j + 3.5k + t * (3i + 2j - k)[/tex]

Open bracket

[tex]r = 2i + 2.4j + 3.5k + 3ti + 2tj - tk[/tex]

Collect like terms

[tex]r = 2i + 3ti+ 2.4j + 2tj+ 3.5k - tk[/tex]

Factorize

[tex]r = (2 + 3t)i+ (2.4 + 2t)j+ (3.5 - t)k[/tex]

The parametric equation is represented as:

[tex]x = x_0 + at\\y = y_0 + bt\\z = z_0 + ct[/tex]

Where

[tex]r = (x_0 + at)i +(y_0 + bt)j+(z_0 + ct)k[/tex]

By comparison:

[tex]x = 2 + 3t\\y = 2.4 + 2t\\z = 3.5-t[/tex]

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