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What value of c makes the equation true?
(PLEASE HELP, and look at the picture)

What Value Of C Makes The Equation True PLEASE HELP And Look At The Picture class=

Sagot :

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Answer:

[tex]\displaystyle c = 8[/tex]

General Formulas and Concepts:

Pre-Algebra

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \frac{3}{6} = \frac{4}{c}[/tex]

Step 2: Solve for c

  1. Simplify [Reduce]:                                                                                             [tex]\displaystyle \frac{1}{2} = \frac{4}{c}[/tex]
  2. [Multiplication Property of Equality] Cross-multiply:                                      [tex]\displaystyle c = 8[/tex]

Answer:

c = 8

Step-by-step explanation:

[tex] \small \sf \frac{3}{6} = \frac{4}{c } \\ [/tex]

  • Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6c, the least common multiple of 6,c.

c × 3 = 6 × 4

  • multiply 6 and 4 to get 24

3c = 24

  • divide both side by 3

[tex]\small \sf \frac{3c }{3} = \frac{ 24} {3} \\ [/tex]

[tex]\small \sf \frac{ \cancel{3}c }{ \cancel{3}} = \frac{ \cancel{24}} {\cancel{3}} \\ [/tex]

  • Divide 24 by 3 to get 8.

c = 8

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