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Sagot :
Answer:
See Explanation
Step-by-step explanation:
(For Diagram please find in attachment)
- Given, Let Assume triangle ABC Where, DE is Parallel to BC & D is midpoint to AB . ∵ AD=DB
- To Prove, E is the midpoint of AC.
- Proof, If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
Since DE∥BC
∴ By Basic Proportionality Theorem,
AD/DB = AE/EC
Since it is Given, AD=DB
∴ AE/EC =1
∴ AE=EC (Proved)
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