tatyavalos1805
Answered

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HELP PLS ITS ALGEBRA 1

HELP PLS ITS ALGEBRA 1 class=

Sagot :

Answer:

[tex] - \frac{2}{6} [/tex]

Step-by-step explanation:

Use distributive property to simplify both sides.

[tex] \frac{1}{6} (1 - 6x) = - \frac{1}{3} ( 6x + \frac{1}{2} )[/tex]

Use the Golden Rule of Algebra: (What we do to one side, we must do to the other).

[tex] \frac{1}{6 } - x = - 2x - \frac{1}{6} [/tex]

[tex] \frac{1}{6} = - x - \frac{1}{6} [/tex]

[tex] \frac{2}{6 } = - x[/tex]

[tex]x = - \frac{2}{6} [/tex]

RexRelative

Answer:

Step-by-step explanation:

[tex]\frac{1}{6}[/tex](1-6x) = - [tex]\frac{1}{3}[/tex](6x+[tex]\frac{1}{2}[/tex])

distribute in the fractions

[tex]\frac{1}{6}[/tex] - 1x = -2x - [tex]\frac{1}{6}[/tex]

subtract [tex]\frac{1}{6}[/tex]  from both sides

-[tex]\frac{1}{6}[/tex]+[tex]\frac{1}{6}[/tex]-1x = -2x -[tex]\frac{1}{6}[/tex]-[tex]\frac{1}{6}[/tex]

-1x = -2x -[tex]\frac{2}{6}[/tex]

-x = -2x - [tex]\frac{1}{3}[/tex]

[tex]\frac{1}{3}[/tex] = -2x + x

[tex]\frac{1}{3}[/tex] = -x

- [tex]\frac{1}{3}[/tex] = x

x = - [tex]\frac{1}{3}[/tex]

see?  :/  

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