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300.0 mL of a 0.335 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

Sagot :

Answer: The new concentration of the solution is 0.143 M.

Explanation:

Given: [tex]V_{1}[/tex] = 300.0 mL,    [tex]M_{1}[/tex] = 0.335 M

[tex]V_{2}[/tex] = 700.0 mL,         [tex]M_{2}[/tex] = ?

Formula used is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute values into the above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.335 M \times 300.0 mL = M_{2} \times 700.0 mL\\M_{2} = 0.143 M[/tex]

Thus, we can conclude that the new concentration of the solution is 0.143 M.