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Sagot :
Answer:
She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.
Step-by-step explanation:
Let x represent the number of times that she travels using the train and let y represent the number of times she travels using the bus. Since she makes at least 8 trips to the place, hence:
x + y ≥ 8
Also, she plans to spend no more than 9 hr in travel time. Hence:
x + 1.5y ≤ 9
x ≥ 0, y ≥ 0.
Plotting the above equations on geogebra online graphing tool, the solution is (6, 2), (8, 0) and (9, 0).
If a train trip costs $6 and a bus trip costs $5, The cost equation (C) is:
C = 6x + 5y
At point (6, 2): C = 6(6) + 5(2) = $46
At point (8, 0): C = 6(8) + 5(0) = $48
At point (9, 0): C = 6(9) + 5(0) = $54
Therefore the minimum cost is at (6, 2). She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.
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