Ceebre
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Using each of the digits 2 through 5 only
once, write 2 two-digit whole numbers
whose product is as large as possible.


Sagot :

Answer:

52, 43

Step-by-step explanation:

the first instinct might be to make the first number as big as possible : 54

that leaves for the second number 2 and 3, and the largest combination here is 32 (larger than 23).

54×32 = 1728

but, the area of a rectangle (and that is what we are calculating here) is the larger, the closer the lengths of its side are.

so, a bigger difference between length and width creates a smaller area, than a smaller difference between length and width for similar lengths.

so, what if we sacrifice just a little bit of the length, and make it 53 ? that opens up 4 for the second number, giving us 42 as width. they are much closer to each other with still very similar length.

53×42 = 2226

you see ? much bigger.

let's experiment further and pick 52 as length.

that gives us 43 as width.

52×43 = 2236

and again a little bit closer and with bigger result.

you see, in the previous case we "added" comparably to this last case a 42 (53×42 instead of 52×42), and in the last case we added a 52 (52×43 instead of 52×42) creating the difference of 10.

but of course, this only works, if we don't decrease the length too much.

Answer:

Using each of the digits 2 through 5 only once, write 2 two-digit whole numbers whose product is as large as possible.