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Sagot :
Given:
The dotted boundary line passes through the points (-3,-8), (1,-2) and (9,10).
Above line is shaded.
To find:
The inequality for the given graph.
Solution:
Consider any two points on the line. Let the two points are (1,-2) and (9,10). So, the equation of the line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-(-2)=\dfrac{10-(-2)}{9-1}(x-1)[/tex]
[tex]y+2=\dfrac{10+2}{8}(x-1)[/tex]
[tex]y+2=\dfrac{12}{8}(x-1)[/tex]
[tex]y+2=\dfrac{3}{2}(x-1)[/tex]
Multiply both sides by 2.
[tex]2(y+2)=3(x-1)[/tex]
[tex]2y+4=3x-3[/tex]
[tex]2y-3x=-3-4[/tex]
[tex]-3x+2y=-7[/tex]
Above line is shaded and the boundary line is a dotted line. So, the sign of inequality must be >.
[tex]-3x+2y>-7[/tex]
This inequality is not in the equations. So, multiply both sides by -1 and change the inequality sign.
[tex](-3x+2y)(-1)<-7(-1)[/tex]
[tex]3x-2y<7[/tex]
Therefore, the correct option is D.
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