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Which polynomial function has a root of 1 with
multiplicity 2 and a root of 6 with multiplicity 1?
Of(x) = (x - 1)(x – 6)
O f(x) = 2(x - 1)(x – 6)
O f(x) = (x - 1)(x - 1)(x – 6)
O f(x) = (x - 1)(x - 6)(x-6)

Sagot :

Answer:

The 3rd:

f(x) = (x - 1)(x - 1)(x – 6)

Step-by-step explanation:

Its roots are the x-values for which f(x)=0, that are:

x1=1

x2=1

x3=6