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A chord is 6cm from the centre of a circle of radius 14cm. calculate the length of the chord with workings​

Sagot :

VirαtKσhli

Answer:

25.28 cm

Step-by-step explanation:

The chord is 6cm away from the centre of the circle . And the radius of the circle is 14 cm . We know that the perpendicular from the centre bisects the chord .

This will form a right angle triangle with the distance between centre and the code as its perpendicular and the length of radius as hypotenuse .

[tex]\implies Base^2+Perpendicular^2=Hypontenuse^2 \\\\\implies b^2 + (6cm)^2=(14cm)^2 \\\\\implies b^2 + 36cm^2= 196cm^2 \\\\\implies b^2 = 196cm^2-36cm^2 \\\\\implies b^2 = 160cm^2 \\\\\implies b=\sqrt{160cm^2}\\\\\implies b = 12.64 cm [/tex]

Hence the required answer is 12.64 × 2 = 25.28cm .

caylus

Hello,

Let's use the Pythagorian 's theorem.

The length of the chord = 8*V10=25,2982.... (cm)

View image caylus
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