Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
25.28 cm
Step-by-step explanation:
The chord is 6cm away from the centre of the circle . And the radius of the circle is 14 cm . We know that the perpendicular from the centre bisects the chord .
This will form a right angle triangle with the distance between centre and the code as its perpendicular and the length of radius as hypotenuse .
[tex]\implies Base^2+Perpendicular^2=Hypontenuse^2 \\\\\implies b^2 + (6cm)^2=(14cm)^2 \\\\\implies b^2 + 36cm^2= 196cm^2 \\\\\implies b^2 = 196cm^2-36cm^2 \\\\\implies b^2 = 160cm^2 \\\\\implies b=\sqrt{160cm^2}\\\\\implies b = 12.64 cm [/tex]
Hence the required answer is 12.64 × 2 = 25.28cm .
Hello,
Let's use the Pythagorian 's theorem.
The length of the chord = 8*V10=25,2982.... (cm)
![View image caylus](https://us-static.z-dn.net/files/db1/2fab4d32db22a1f454775383002bdf37.gif)
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.