Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.7 m/s . It then flies a further distance of 48500 m , and afterwards, its velocity is 44.7 m/s . Find the airplane's acceleration.

Sagot :

KimYurii

Answer:

[tex]\quad[/tex]0.0095 m/s²

Explanation:

We have,

  • Initial velocity (u) = 32.7 m/s
  • Final velocity (v) = 44.7 m/s
  • Distance travelled (s) = 48500 m

We are asked to calculate the airplane's acceleration.

By using the third equation of motion,

➝ v² - u² = 2as

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • s denotes distance

➝ (44.7)² - (32.7)² = 2 × a × 48500

➝ 1998.09 - 1069.29 = 97000 × a

➝ 928.8 = 97000a

➝ 928.8 ÷ 97000 = a

➝ 0.0095 m/s² = a

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.