Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Find the TWO integers whos product is -12 and whose sum is 1
​

Sagot :

VirαtKσhli

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Nayefx

Answer:

[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]

Step-by-step explanation:

we are given two conditions

  1. two integers whos product is -12
  2. two integers whos sum is 1

let the two integers be x and y respectively according to the first condition

[tex] \displaystyle xy = - 12[/tex]

according to the second condition:

[tex] \displaystyle x + y = 1[/tex]

now notice that we have two variables therefore ended up with a simultaneous equation so to solve the simultaneous equation cancel x from both sides of the second equation which yields:

[tex] \displaystyle y = 1 - x[/tex]

now substitute the got value of y to the first equation which yields:

[tex] \displaystyle x(1 - x) = - 12[/tex]

distribute:

[tex] \displaystyle x- {x}^{2} = - 12[/tex]

add 12 in both sides:

[tex] \displaystyle x- {x}^{2} + 12 = 0[/tex]

rearrange it to standard form:

[tex] \displaystyle - {x}^{2} + x + 12 = 0[/tex]

divide both sides by -1:

[tex] \displaystyle {x}^{2} - x - 12 = 0[/tex]

factor:

[tex] \displaystyle ({x} + 3)(x - 4) = 0[/tex]

by Zero product property we acquire:

[tex] \displaystyle {x} + 3 = 0\\ x - 4= 0[/tex]

solve the equations for x therefore,

[tex] \displaystyle {x}_{1} = - 3\\ x _{2} = 4[/tex]

when x is -3 then y is

[tex] \displaystyle y _{1}= 1 - ( - 3)[/tex]

simplify

[tex] \displaystyle y _{1}= 4[/tex]

when x is 4 y is

[tex] \displaystyle y _{2}= 1 - ( 4)[/tex]

simplify:

[tex] \displaystyle y _{2}= - 3[/tex]

hence,

[tex] \displaystyle( {x}_{1} , y_{1}) =( - 3,4)\\ (x _{2}, y_{2}) = (4, - 3)[/tex]

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.