Answer:
[tex] \rm Numbers = 4 \ and \ -3.[/tex]
Step-by-step explanation:
Given :-
The sum of two numbers is 1 .
The product of the nos . is 12 .
And we need to find out the numbers. So let us take ,
First number be x
Second number be 1-x .
According to first condition :-
[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]
Hence the numbers are 4 and -3
Answer:
Step-by-step explanation:
If the product of 2 integers is -12, then that equation looks like this:
xy = -12
If the sum of those same 2 integers in 1, then that equation looks like this:
x + y = 1
Let's solve the second equation for x and plug it into the first equation. Solving the second equation for x gives us
x = 1 - y and plug that into the first equation in place of x to get:
(1 - y)y = -12 and
[tex]y-y^2=-12[/tex] Now move everything over to one side and factor to find y:
[tex]-y^2+y+12=0[/tex] and the 2 values for y are
y = -3 and y = 4. Let's see what happens when we solve for x.
If xy = -12 and y is -3:
x(-3) = -12 so
x = 4
If xy = -12 and y is4:
x(4) = -12 so
x = -3
So it looks like the 2 integers are -3 and 4
