blessbaez16
Answered

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What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

Sagot :

Cricetus

Answer:

The volume will be "2.95 L".

Explanation:

Given:

n = 0.104

p = 0.91 atm

T = 314 K

Now,

The Volume (V) will be:

= [tex]\frac{nRT}{P}[/tex]

By putting the values, we get

= [tex]\frac{0.104\times 0.0821\times 314}{0.91}[/tex]

= [tex]\frac{2.6810}{0.91}[/tex]

= [tex]2.95 \ L[/tex]

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