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3 years later a mother will be 4 times as
old as her son. 3 years ago ,the mother age was two times as old as her son age will be 8 years hence. What are their present ages?​


Sagot :

Answer:

  • 33 and 6 years

Step-by-step explanation:

  • Mother's age = m
  • Son's age = s

3 years later:

  • m + 3 = 4(s + 3) ⇒ m = 4s + 12 - 3 = 4s + 9

3 years ago:

  • m - 3 = 2(s + 8) ⇒ m = 2s + 18 + 3 = 2s + 21

Solve for s by substitution:

  • 4s + 9 = 2s + 21
  • 2s = 12
  • s = 6

Find the value of m:

  • m = 4*6 + 9 = 33

Mother is 33 and son is 6