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Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the electron is 5.3×10^-11

Sagot :

okpalawalter8

Answer:

[tex]F=-8.2*10^{-8}N[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=5.3*10^{-11}[/tex]

Where

Proton Charge [tex]q_1=1.6*10^{-19}C[/tex]

Charge of Electron [tex]q_2=-1.6*10^{-19}C[/tex]

Generally the equation for Coulomb's Law is mathematically given by

 [tex]F=\frac{9*10^9(q_1)(q_2)}{r^2}[/tex]

 [tex]F=\frac{9*10^9(1.6*10^{-19}C)(-1.6*10^{-19}C)}{5.3*10^{-11}}[/tex]

 [tex]F=-8.2*10^{-8}N[/tex]

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