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A man is twice as old as his son. Five years ago, the ratio of their ages was 9:4. Find the son's present age

Sagot :

RudabaManan

Answer:

Son's age is 25.

Step-by-step explanation:

Let the Father's age be 2x.

Let the son's age be x.

Five years ago:

Man's age will be = 2x - 5

Son's age will be = x - 5

If the ratio of their ages five years ago was 9:4, then:

2x - 5/x-5 = 9/4

⇒ 4(2x - 5) = 9(x - 5)

⇒ 8x - 20 = 9x - 45

⇒ -20 + 45 = 9x - 8x

⇒ 25 = x

∴ x = 25

Hence, the son's age = 25 years

If x = 25, the father's age (2x) will be 2 × 25 = 50 years

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