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Mike invested $93,000 at 8.19% compounded weekly.
What will Mike's account balance be in 11 years?

Sagot :

Answer:

$4920446.6202

Step-by-step explanation:

the formula for compound interest is: P(1+ r/n)^n*t

p= principle (the amount of money you invest/ start with)

r= the interest rate (which is the percentage in decimal)

n= the number of times its compounded per year (52 weeks per year)

t= the amount of time (usually in years)

now, you plug the numbers youre given into the formula:

93000(1+0.0819/52)^52*11

= $4920446.62402

hope this helps :)

Mile's account balance after 11 years will be $228,786.8

What is the formula for compound interest?

"[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

where A = Accrued amount (principal + interest)

P = Principal amount

r = interest rate as a decimal

R = interest rate as a percent

r = R/100

n = number of compounding periods

t = time in years"

For given question,

P = $93000,

t = 11 years

n = 52 (weekly compounding)

R = 8.19%

So, the interest rate in decimal would be,

[tex]\Rightarrow r =\frac{8.19}{100}\\\\\Rightarrow r =0.0819[/tex]

Using the formula of compound interest,

[tex]\Rightarrow A=P(1+\frac{r}{n} )^{nt}\\\\\Rightarrow A=93000(1+\frac{0.0819}{52} )^{52\times 11}\\\\\Rightarrow A=93000(1+\frac{0.0819}{52} )^572\\\\\Rightarrow A=228,786.8[/tex]

Therefore, Mile's account balance after 11 years will be $228,786.8

Learn more about the compound interest here:

https://brainly.com/question/22979103

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