Answered

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Question 8: Find the equation of the straight line that:
(a) has a gradient of 4 and passes through the point (1, 10)

Sagot :

theleangreenbean

Answer:

[tex]y=4x+6[/tex]

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope (also called the gradient) and b is the y-intercept (the value of y when x is 0)

1) Plug the gradient into the equation (b)

[tex]y=mx+b[/tex]

We're given that the gradient of the line is 4. Plug this into [tex]y=mx+b[/tex] as m:

[tex]y=4x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=4x+b[/tex]

Plug in the given point (1,10) as (x,y) and solve for b

[tex]10=4(1)+b\\10=4+b[/tex]

Subtract 4 from both sides to isolate b

[tex]10-4=4+b-4\\6=b[/tex]

Therefore, the y-intercept of the line is 6. Plug this back into [tex]y=4x+b[/tex] as b:

[tex]y=4x+6[/tex]

I hope this helps!

ashish4112119

answer = y = 4x + 6

y = mx + b

gradient = slope = m = 4

(1,10) = (x,y)

plug in the values

10 = 4 (1) + b

10 = 4 + b

b = 6

y = 4x + 6

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