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The graph of a line goes through the points (-4,3) and (6,8). What is the equation of the line in slope-intercept form?
Enter the correct answer in the box by replacing m and b with the appropriate values.
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7/3/2001

The Graph Of A Line Goes Through The Points 43 And 68 What Is The Equation Of The Line In Slopeintercept Form Enter The Correct Answer In The Box By Replacing M class=

Sagot :

theleangreenbean

Answer:

[tex]y=\frac{1}{2}x+5[/tex]

Step-by-step explanation:

Hi there!

Slope intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that lie on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug the given points (-4,3) and (6,8) into the equation

[tex]m=\frac{8-3}{6-(-4)}\\m=\frac{8-3}{6+4}\\m=\frac{5}{10}\\m=\frac{1}{2}[/tex]

Therefore, the slope of the line is [tex]\frac{1}{2}[/tex]. Plug this into [tex]y=mx+b[/tex] :

[tex]y=\frac{1}{2}x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=\frac{1}{2}x+b[/tex]

Plug in one of the given points and solve for b

[tex]8=\frac{1}{2}(6)+b\\8=3+b[/tex]

Subtract 3 from both sides to isolate b

[tex]8-3=3+b-3\\5=b[/tex]

Therefore, the y-intercept is 5. Plug this back into [tex]y=\frac{1}{2}x+b[/tex]:

[tex]y=\frac{1}{2}x+5[/tex]

I hope this helps!

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