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Sagot :
Answer:
Step-by-step explanation:
Using log(x) - log(y) = log (x/y)
logx^2 - log(x+6) = 1 is equal to:
log (x^2/(x+6)) = 1
Taking inverse base 3 log on both side:
x^2/(x+6) = 3
x^2 = 3x + 18
x^2 - 3x - 18 = 0
(x-6)(x+3) = 0
x = 6 or -3
Answer:
Step-by-step explanation:
1 = base 3log3
substitute
logx^2-log(x+6) = log3
logx^2 - log(x+6) - log3 = 0
log( (x^2/(x+6))/3 ) = 0
anti-log
x^2/3(x+6) = 1
x^2 = 3(x+6)
x^2-3x-18=0
x=6 n -3
anti-log base 3 on both sides:
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