Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Score for Question 2: ___ of 5 points) 2. Write the equation of the circle in general form. Show your work.

Sagot :

MrRoyal

Answer:

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

Step-by-step explanation:

Given

See attachment for circle

Required

The circle equation

First, we get the radius of the circle.

From the attachment, we have:

[tex]r = 3[/tex]

Next, the center of the circle

[tex](h,k) = (-1,1)[/tex]

The equation of the circle is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

This gives:

[tex](x - -1)^2 + (y - 1)^2 = 3^2[/tex]

[tex](x +1)^2 + (y - 1)^2 = 3^2[/tex]

Expand

[tex]x^2 + 2x + 1 + y^2 - 2y + 1 = 9[/tex]

Collect like terms

[tex]x^2 + y^2 + 2x - 2y + 1 + 1 - 9 = 0[/tex]

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

Hence, the equation in general form is:

[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]

View image MrRoyal
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.