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Sagot :
Answer:
20 units
Step-by-step explanation:
Let the length be x. According to the question,
- Length = x
- Width = 15% of the length
➝ Width = 15% of the length
➝ Width = 15/100x
➝ Width = 3/20x
We have the perimeter of the rectangle that is 46 units.
[tex]\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\ [/tex]
[tex]\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\ [/tex]
[tex]\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\ [/tex]
[tex]\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\ [/tex]
[tex]\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\ [/tex]
[tex]\longrightarrow \sf {\dfrac{46}{2}= \dfrac{23x}{20}} \\ [/tex]
[tex]\longrightarrow \sf {23= \dfrac{23x}{20}} \\ [/tex]
[tex]\longrightarrow \sf {23 \times 20 = 23x} \\ [/tex]
[tex]\longrightarrow \sf {460= 23x} \\ [/tex]
[tex]\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\ [/tex]
[tex]\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\ [/tex]
Therefore, length of the rectangle is 20 units.
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