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Sagot :
Answer:
The volume (density) of cement that will be needed to cover this hollow pipe is:
= 50,000 kg/m³
Step-by-step explanation:
Length of a cylindrical pipe = 5m
Width of the cylindrical pipe = 4m
Depth of the cylindrical pipe = 2.5m
The cubic meters of the cylindrical pipe = 5 * 4 * 2.5 = 50m³
1 cubic meter is equal to 1,000 kilogram
Therefore, the volume (density) of cement that will be needed to cover this hollow pipe is:
= 50 * 1,000
= 50,000 kg/m³
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