Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
I don’t know if I did this right, but I hope it helps.
Molar mass of BF3
M(BF3) = (1x10.8) + (3x18.91)
= 67.53 grams per mol
Molar mass of Boron in BF3
M(B) = 1x10.8 = 10.8 grams per mol
5.35x10^22 molecules of BF3 into mol
n = N/NA
n(BF3) = 5.35x10^22/6.02x10^23
= 8.89x10^44 mol of BF3
Mass of B in BF3
m = n x M
m(b) = 8.89x10^44 x 10.8
= 9.6x10^45g
Molar mass of BF3
M(BF3) = (1x10.8) + (3x18.91)
= 67.53 grams per mol
Molar mass of Boron in BF3
M(B) = 1x10.8 = 10.8 grams per mol
5.35x10^22 molecules of BF3 into mol
n = N/NA
n(BF3) = 5.35x10^22/6.02x10^23
= 8.89x10^44 mol of BF3
Mass of B in BF3
m = n x M
m(b) = 8.89x10^44 x 10.8
= 9.6x10^45g
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
