parisintrees
Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Someone please help me I’m literally struggling

Someone Please Help Me Im Literally Struggling class=

Sagot :

Hello,

We have :

27 = 3³ = 3 × 3 × 3

[tex]x[/tex]³ = [tex]x[/tex] × [tex]x[/tex] × [tex]x[/tex]

So :

The cube root of 27[tex]x[/tex]³ is :

3 × [tex]x[/tex] = 3[tex]x[/tex]

(  because : (3[tex]x[/tex])³ = 27[tex]x[/tex]³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2

[tex]a^{3} +b^{3} = (a+b)(a^{2} -ab+b^{2} )[/tex] with [tex]a=3x[/tex] and [tex]b=2[/tex]

We have :

[tex](3x)^{3}+2^{3}=(3x+2)((3x)^{2} -(3x)(2)+(2 )^{2} )[/tex]

Have a nice day :)
The first question will be 3x to the power of 3
The second one will 2
The third will substitute a and put 3x and substitute b and but 2
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.