parisintrees
Answered

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Someone please help me I’m literally struggling

Someone Please Help Me Im Literally Struggling class=

Sagot :

Hello,

We have :

27 = 3³ = 3 × 3 × 3

[tex]x[/tex]³ = [tex]x[/tex] × [tex]x[/tex] × [tex]x[/tex]

So :

The cube root of 27[tex]x[/tex]³ is :

3 × [tex]x[/tex] = 3[tex]x[/tex]

(  because : (3[tex]x[/tex])³ = 27[tex]x[/tex]³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2

[tex]a^{3} +b^{3} = (a+b)(a^{2} -ab+b^{2} )[/tex] with [tex]a=3x[/tex] and [tex]b=2[/tex]

We have :

[tex](3x)^{3}+2^{3}=(3x+2)((3x)^{2} -(3x)(2)+(2 )^{2} )[/tex]

Have a nice day :)
The first question will be 3x to the power of 3
The second one will 2
The third will substitute a and put 3x and substitute b and but 2
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