parisintrees
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Someone please help me I’m literally struggling

Someone Please Help Me Im Literally Struggling class=

Sagot :

Hello,

We have :

27 = 3³ = 3 × 3 × 3

[tex]x[/tex]³ = [tex]x[/tex] × [tex]x[/tex] × [tex]x[/tex]

So :

The cube root of 27[tex]x[/tex]³ is :

3 × [tex]x[/tex] = 3[tex]x[/tex]

(  because : (3[tex]x[/tex])³ = 27[tex]x[/tex]³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2

[tex]a^{3} +b^{3} = (a+b)(a^{2} -ab+b^{2} )[/tex] with [tex]a=3x[/tex] and [tex]b=2[/tex]

We have :

[tex](3x)^{3}+2^{3}=(3x+2)((3x)^{2} -(3x)(2)+(2 )^{2} )[/tex]

Have a nice day :)
The first question will be 3x to the power of 3
The second one will 2
The third will substitute a and put 3x and substitute b and but 2
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.