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Find the nature of roots for equation 2x square -root5x -2 =0
Pls help me fast

Sagot :

Answer:

roots are real and distinct

Step-by-step explanation:

To determine the nature of the roots use the discriminant , b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct roots

• If b² - 4ac = 0 then 2 real and equal roots

• If b² - 4ac < 0 then roots are not real

Given

2x² - [tex]\sqrt{5}[/tex] x - 2 = 0

with a = 2, b = - [tex]\sqrt{5}[/tex] , c = - 2 , then

b² - 4ac

= (- [tex]\sqrt{5}[/tex] )² - ( 4 × 2 × - 2)

= 5 - (- 16)

= 5 + 16

= 21

Since b² - 4ac > 0 then the equation has 2 real and distinct roots

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