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find the first four terms and the tenth term
a) 3n^2

Sagot :

Step-by-step explanation:

3n^2

First term => n=1 => 3(1)^2 =>3

Second term => n=2 => 3(2)^2 =>3x4=12

Third term => n=3 => 3(3)^2 =>3x9=27

Fourth term => n=4 => 3(4)^2 =>3x16=48

Tenth term => n=10 => 3(1)^2 =>3x10=300

Answer:

{3, 12, 27, 48, 300}

Step-by-step explanation:

For the first four terms, n = {1, 2, 3, 4}.  For the tenth, n = {10}.

Then, applying the formula a(n) = 3n^2 to n = {1, 2, 3, 4, 10}, we get:

{3(1)², 3(2)², 3(3)², 3(4)², 3(10)²} = {3, 12, 27, 48, 300}

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