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How many odd numbers greater than 60000 can be formed, using numbers 2,3,4,5 and 6 if each digit is used only once in each number?​

Sagot :

caylus

Hello,

All the numbers must begin with  6.

There are still 2,3,4,5 digits :  4 possibilities.

4!=4*3*2*1=24

The first is 62345 and the last 65432.