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A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container B.) find the volume of the container

Sagot :

Answer:

Step-by-step explanation:

Surface:

surface area = 2 ends + side

The ends are both a circle and they are identical.

area of a circle = [tex]\pi[/tex][tex]r^{2}[/tex]

then  [tex]\pi[/tex][tex]7^{2}[/tex] = 153.93804 [tex]cm^{2}[/tex]

since there are two ends multiply the above by 2

2*153.93804 =307.87608 [tex]cm^{2}[/tex]

the side is the length * height

length = perimeter of the circle , the perimeter of a circle is also the circumference.   circ = 2[tex]\pi[/tex]r

circ = 2*[tex]\pi[/tex]*7 = 53.407075

surface area of the side = 6* 53.407075=320.44245

add the two surfaces areas together :)

total surface area = 320.44245 + 307.87608 = 628.3185307 [tex]cm^{2}[/tex]

Volume:

volume is the area of the end times the height

volume = circle area * height

volume = 153.93804 * 6

volume = 923.62824 [tex]cm^{3}[/tex]