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can anyone answer this? (2y²-3xy)÷y.​

Sagot :

the answer would be y x(2y-3x)

Answer:

2y - 3x

Step-by-step explanation:

Given

(2y² - 3xy) ÷ y

Divide each term on the numerator by y , that is

[tex]\frac{2y^2}{y}[/tex] - [tex]\frac{3xy}{y}[/tex] ( cancel y on numerator/ denominator of both fractions )

= 2y - 3x