Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Divided 29 into two parts so that the sum of the squares of the parts is 425 . Find the value of each part.​

Sagot :

Answer:

Step-by-step explanation:

Equations

x + y = 29

x^2 + y^2 = 425

Solution

y = 29 - x

x^2 + (29 - x)^2 = 425

x^2 + (841 - 58x + x^2 ) = 425

x^2 - 58x + x^2 + 841 - 425 = 0

2x^2 - 58x +416 = 0

a = 2

b = - 58

c = 416

You get two answers that look valid

2x^2 - 58x + 416 = 0

x^2 - 29x + 208 = 0           This factors

(x - 16)(x - 13) = 0

x = 16

y = 13

Now check it

16^2 + 13^2 = ? 425

256 + 169 =  425