Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Divided 29 into two parts so that the sum of the squares of the parts is 425 . Find the value of each part.​

Sagot :

jcherry99

Answer:

Step-by-step explanation:

Equations

x + y = 29

x^2 + y^2 = 425

Solution

y = 29 - x

x^2 + (29 - x)^2 = 425

x^2 + (841 - 58x + x^2 ) = 425

x^2 - 58x + x^2 + 841 - 425 = 0

2x^2 - 58x +416 = 0

a = 2

b = - 58

c = 416

You get two answers that look valid

2x^2 - 58x + 416 = 0

x^2 - 29x + 208 = 0           This factors

(x - 16)(x - 13) = 0

x = 16

y = 13

Now check it

16^2 + 13^2 = ? 425

256 + 169 =  425

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.