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Angle ABC has A(3-,6), and C(9,55 as it vertices.
What is the length of side AB in units?

Sagot :

MrRoyal

Answer:

7.07 units

Step-by-step explanation:

Given

[tex]A = (-3,6)[/tex]

[tex]B = (2,1)[/tex]

[tex]C = (9,5)[/tex]

See comment for complete question

Required

Side length AB

To do this, we make use of the following distance formula;

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

So, we have:

[tex]d = \sqrt{(-3 - 2)^2 + (6 - 1)^2}[/tex]

[tex]d = \sqrt{(-5)^2 + 5^2}[/tex]

[tex]d = \sqrt{25 + 25}[/tex]

[tex]d = \sqrt{50}[/tex]

[tex]d = 7.07[/tex]

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