stephensm
Answered

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Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Sagot :

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

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