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Sagot :
Answer:
[tex]{ \bf {factor : { \tt{x - 1}}}} \\ x - 1 = 0 \\ x = 1 \\ { \tt{f(x) = {x}^{3} - {3x}^{2} + kx - 1}} \\ { \tt{f(1) : {(1)}^{3} - 3 {(1)}^{2} + k(1) - 1 = 0}} \\ { \tt{k - 3 = 0}} \\ { \tt{k = 3}}[/tex]
Answer:
k = 3
Step-by-step explanation:
If x-1 is a factor of x³ - 3x² + kx - 1 then value of x is 1.
f (x ) = x³ - 3x² + Kx - 1 , then
plug 1 as x in the expression.
- f ( 1) = ( 1)³ - 3 ( 1)² + k (1) - 1 = 0
expand exponents
- 1 - 3 + k - 1 = 0
combine like terms
- -3 + k = 0
Add 3 to both side
- k = 3
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