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Sagot :
The probability of all men = 0.4219 while the probability of 2 women and 1 man = 0.14
How to solve for the probability of men
The question says we have three times as much men as women
The probability it is a man that was chosen = 3/4
The probability of choosing a woman = 1/4
a. The probability that the chosen persons are all men = (3/4)³
= 0.4219
b. The probability of 2 women and 1 man
3 * 0.75 *0.25²
= 0.14
Hence the probabilities are a. 0.4219 and b. 0.14
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